CH3OH+ CH3-CH(OH)-CH3 = CH3-O-CH-CH3 +H2O
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CH3
n(CH3OH)=16/32=0,5моль;
n(CH3-CH(OH)-CH3)=22,5/60=0,375моль;
метанол в избытке! Значит , n(эфира) =0,375г; m(эфира) =0,375*74=27,75г.
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