Решите пожалуйста!!!

Решите задачу:

$27x-28=29x-32 \\ 27x-29x=-32+28 \\ -2x=-4 \\ x=2 \\ \\ -3(4x-8)=4(7x+9) \\ -12x+24=28x+36 \\ -12x-28x=36-24 \\ -40x=12 \\ x=-0.3 \\ \\ 17-(18x+42)=12x+(15-10x) \\ \\ 17-18x-42=12x+15-10x \\ -18x-12x+10x=15-17+42 \\ -20x=40 \\ x=-2$

$\frac{7}{10}x+ \frac{8}{9}= \frac{5}{8}x- \frac{5}{6} \\ \frac{7}{10}x- \frac{5}{8}x =- \frac{5}{6}- \frac{8}{9} \\ \frac{28x-25x}{40}= \frac{-30-32}{36} \\ \frac{3x}{40}=- \frac{62}{36} \\ x=-22 \frac{26}{27} \\ \\ \frac{4x-5}{3}= \frac{11-9x}{5} \\ 5(4x-5)=3(11-9x) \\ 20x-25=33-27x \\ 47x=58 \\ x=1.234 \\ \\ 16x+18=(11+9x)(-2) \\ 16x+18= -22-18x \\ 34x=-40 \\ x=-1 \frac{6}{34}$