3sin(π/2+t)-sin(3π/2+t)-8cos(2π-t)

Question

3sin(π/2+t)-sin(3π/2+t)-8cos(2π-t)

Answer 1

3sin( + t) - sin( + t) - 8cos( - t) = 3cost + cost - 8cost = 4cost - 8cost = -4cost