Sinx-cosy=0/sin²(x)+cos²(y)=2

Question

Sinx-cosy=0/sin²(x)+cos²(y)=2

Answer 1

Sinx-cosy=0⇒sinx=cosy
sin²x+cos²y=2
cos²y+cos²y=2
cos²y=1⇒cosy=-1U cosy=1
(1+cos2y)/2=1
1+cos2y=2
cos2y=1
2y=2πn
y=πn
1)sinx=-1⇒x=-π/4+2πn
2)sinx=1⇒x=π/4+2πn