А) y<3, тогда<br>y-3<0, y-5<0<br>(y-3)(y-5)>0
3-y>0, y-5<0<br>(3-y)(y-5)<0<br>
5-y>0, 3-y>0
(5-y)(3-y)>0
б) у>5
y-3>0, y-5>0
(y-3)(y-5)>0
3-y<0, y-5>0
(3-y)(y-5)<0<br>
5-y<0, 3-y<0<br>(5-y)(3-y)>0
в) 3 y-3>0, y-5<0<br>(y-3)(y-5)<0<br>
3-y<0, y-5<0<br>(3-y)(y-5)>0
5-y>0, 3-y<0<br>(5-y)(3-y)<0