Решите √2х-1+√х-2=√х+1
2x-1≥0 x≥1/2 x-2≥0 x≥2 ⇒x≥2⇒x∈I2;∞) x+1≥0 x≥-1 2x-1=x- 2-2√(x+1)(x-2)+x+1 -2√x²-x-2=0 √x²-x-2=0 x²-x-2=0 D=1+4*2=9 X₁=(1+3):2=2, X₂=(1-3):2=-1, -1 ne ≥ 2, ne reshenie 2≥2 ono reshenie⇒x=2