CH3-CHCl-CH3 + Mg= CH3-CH-CH3
I
Mg-Cl
n(C3H7Cl)= 31,4 : 78,5=0,4моль; n(C3H7MgCl)= 0,4моль;
m(C3H7MgCl)теорет. =0,4*102,5=41г;
m(C3H7MgCl)практ. =41*0,488=20г.
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