2+2sin^2x\sinx+cosx=3sinx

Question

2+2sin^2x\sinx+cosx=3sinx

Answer 1

2sinx(cosx+sinx)=(cosx-sinx)(cosx+sinx)
cosx=-sinx  tgx=-1  x=-П/4+Пn
2sinx=cosx-sinx
3sinx=cosx
tgx=1/3
x=arctg(1/3)+Пn