6sin^2x - 5sinx-4=0 [-7 пи /2 ; -3 пи/2]
Sinx=a 6a²-5a-4=0 D=25+96=121 a1=(5-11)/12=-1/2⇒sinx=-1/2 x=-π/6+2πn -7π/2≤-π/6+2πn≤-3π/2 -21≤-1+12n≤-9 -20≤12n≤-8 -5/3≤n≤-2/3 n=-1 x=-π/6-2π=-13π/6 a2=(5+11)/12=4/3⇒sinx=4/3>1 нет решения