Y=1+ctg (2x-pi) help me pleas, good luck

Question

Y=1+ctg (2x-pi) help me pleas, good luck

Answer 1

У = 1 +ctq(2x -π) =1 +ctq(-(π-2x)) =1 -ctq(π -2x) =1 -ctq2x.
y(xo) = y(π/4) = 1 -ctq(2*π/4) =1 -ctqπ/2 =1 -0 =1.

Comments

y=1+ctg ( 2x - pi )в точке x°=-pi/4