2sin(п/3-2x)cos(x+п/6)+sin(3x-п/6)

Question

2sin(п/3-2x)cos(x+п/6)+sin(3x-п/6)

Answer 1

cos(p/6)*sin(3*x)-sin(p/6)*cos(3*x)-(2*cos(p/6)*cos(p/3)*cos(x)-2*sin(p/6)*cos(p/3)*sin(x))*sin(2*x)-(2*sin(p/6)*sin(p/3)*sin(x)-2*cos(p/6)*sin(p/3)*cos(x))*cos(2*x)