-16ab+8(a+b)^2 при a= \sqrt 14 b= \sqrt5

Question

-16ab+8(a+b)^2 при a= \sqrt 14 b= \sqrt5

Answer 1

=-16ab+8(a²+b²+2ab)=-16ab+8a²+8b²+16ab=8(a²+b²)=8(√14²+√5²)=8*(14+5)=8*19=8*20-8*1=192