4(Х+3)-(0.5Х+1)(2Х+6)<6

Question

4(Х+3)-(0.5Х+1)(2Х+6)<6

Answer 1

4x+12-x2-5x-6-6<0</p>

-x2-x<0</p>

x2+x>0

x(x+1)>0

x1=0     x+1=0

              x2=-1

Answer 2

4x+12-x^2-3-2x-5x-6<0</p>

-x2-x<0</p>

x2+x>0

x(x+1)>0

x1=0     x+1=0

              x2=-1