Решить неравенство 2x^2-7x>0

Решите задачу:

$2x^2-7x\ \textgreater \ 0\rightarrow 2(x^2- \frac{7}{2}x)\ \textgreater \ 0\rightarrow x^2- \frac{7}{2}x\ \textgreater \ 0 \\ \\ x(x- \frac{7}{2})\ \textgreater \ 0 \\ \\ \alpha) \left \{ {{x\ \textgreater \ 0} \atop {x\ \textgreater \ \frac{7}{2} }} \right. \rightarrow x\in(3,5;+\infty) \\ \\ \beta) \left \{ {{x\ \textless \ 0} \atop {x\ \textless \ \frac{7}{2} }} \right. \rightarrow x\in(-\infty;0) \\ x\in(-\infty;0)\vee(3,5;+\infty)$