(x-12)(x+2)-(x+4)(x-4)=32

Question

(x-12)(x+2)-(x+4)(x-4)=32

Answer 1

(х-12)(х+2)-(х+4)(х-4)=32
х²+2х-12х-24-(х²-16)-32=0
х²-10х-24х-х²+16-32=0
-10х-40=0
-10х=40
х= -4

Answer 2

Х^2+2х-12х-24-х^2+16=32, -10х = 32-16+24 -10х = 40, х = - 4