10 √3 -√ 48 - √75 помогите плиз(5√2-√18)*√2 (3-√2)на верху с копки 2

1)
$10\sqrt{3}-\sqrt{48}-\sqrt{75}=10\sqrt{3}-\sqrt{3}*\sqrt{16}-\sqrt{3}*\sqrt{25}=\\=\sqrt{3}(10-\sqrt{16}-\sqrt{25})=\sqrt{3}(10-4-5)=\sqrt{3}$

2)
$(5\sqrt{2}-\sqrt{18})\sqrt{2}=5\sqrt{2*2}-\sqrt{18*2}=5\sqrt{4}-\sqrt{36}=5*2-6=4$

3)
$(3-\sqrt{2})^2=3^2-2*3*\sqrt{2}+(\sqrt{2})^2=9-6\sqrt{2}+2=11-6\sqrt{2}$

10 √3 -√ 48 - √75 помогите плиз(5√2-√18)*√2 (3-√2)** верху с копки 2