2sin^2(4x)-4=3sin4x*cos4x-4cos^2(4x)

Question

2sin^2(4x)-4=3sin4x*cos4x-4cos^2(4x)

Answer 1

2sin^2(4x)-4=3sin4x*cos4x-4cos^2(4x)
2sin^2(4x)-4+4cos^2(4x)=3sin4xcos4x
4(sin^2(4x)+cos^2(4x))-4-2sin^2(4x)=3sin4xcos4x
3sin4xcos4x+2sin^2(4x)=0
3ctg4x+2=0
ctg4x=-2/3
x=-1/4arcctg(2/3)+Пk