Решить неравенства....

Решите задачу:

$3^{x+2}\ \textless \ \frac{1}{9}\\ 3^{x+2} \ \textless \ 3^{-2}\\ x+2 \ \textless \ -2 \\ x\ \textless \ -4$

$4^{x+2} \geq \frac{1}{8} \\ 2^{2x+4} \geq 2^{-3}\\ 2x+4 \geq -3\\ 2x \geq -7\\ x \geq -3.5$

$2^{3x+2} \ \textless \ \frac{1}{8} \\ 2^{3x+2}\ \textless \ 2^{-3}\\ 3x+2 \ \textless \ -3\\ 3x \ \textless \ -5\\ x\ \textless \ - \frac{5}{3}$

$2^{4x-5} \geq \frac{1}{8} \\ 2^{4x-5} \geq 2^{-3}\\ 4x-5 \geq -3\\ 4x \geq 2\\ x \geq 0.5$