(6y-4)(y-4)=7(y2-4y-12)

Question

(6y-4)(y-4)=7(y2-4y-12)

Comments

с правой стороны первый у в квадрате?

Answer 1

6y2 - 24y - 4y +16 = 7y2 - 28y - 84
6y2 - 24y - 4y - 7y2 +28y = -100
-y2 = -100
y=10