Решите неравенство 2/(8^х-10) ≥4/(8^х-8)
2/(8^x - 10)-4/(8^x - 8)≥0 8^x=a (2/(a-10)-4/(a-8)≥0 (2a-16-4a+40)/(a-10)(a-8)≥0 (24-2a)/(a-8)(a-10)≥0 24-2a=0⇒a=12 a-10=0⇒a=10 a-8=0⇒a=8 + _ + _ -------------------------------------------------- 8 10 12 a<8⇒8^x<8⇒x<1⇒x∈(-∞;1)<br>10Ответ x∈(-∞;1) U (log(8)10;log(8)12]